As per IS 456 : 2000 Clasue 6.2.3.1 Page No. 16. M odulus of elasticity of Concrete can be calculated by following formula: Ec = 5000 √fck N/mm2 Where Ec is short term static modulus of electricity. Actual measured values may differ by plus minus 20 % from the values obtained from the above expression. Example :- Q. As per IS 456:2000 , which one of the following correctly expresses the modulus of elasticity of Concrete ? a) Ec = 0.7 √fck N/mm2 b) Ec = 500 √fck N/mm2 c) Ec = 5000 √ fck N/mm2 d) Ec = 5700√fck N/mm2 Correct Answer is c ) Option. Thanks for reading this article. If you find this article helpful please, don’t forget to share and Subscribe Afroz Civil website and YouTube Channel for Latest Update. I hope this article will be helpful for every Engineer. 😍Join Our YouTube Channel Click here 😍Join Our Facebook page Click here I always Update helpful information and share my practical experience at this site. Please Give your ...
Welcome to Afroz Civil – your trusted hub for civil engineering knowledge, practical insights, and the latest innovations in construction technology. Our mission is to empower engineers, contractors, and project managers with effective solutions to real-world challenges on construction sites. From theory to practice, we bridge the gap by sharing expert guidance, modern techniques, and proven strategies to ensure smarter, safer, and more efficient project execution.